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## What happens chemically when quicklime is added to water?

**Ask: **What happens chemically when quicklime is added to water?

It produces slaked lime (calcium hydroxide)

Hope this helped!

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Quicklime is also known as Calcium oxide (CaO)

By [displacement] chemical reaction, this will happen if Quicklime (CaO) is added to water (H2O):

CaO + [tex] H_{2} [/tex] OÂ â†’ Ca + [tex] (OH)_{2} [/tex]Â

Quicklime + water = Calcium Hydroxide

## is a mixture of quicklime or cement combined with sand

**Ask: **is a mixture of quicklime or cement combined with sand and waterâ€‹

**Answer:**

LIME MORTAR

sana po makatulong:))

## erns as he KCLO3 KCI + O2 IS 4. The

**Ask: **erns as he KCLO3 KCI + O2 IS 4. The correct coefficients for the equation A 2.2,3 C. 2,3,2 B. 3,2,3 D. 2,1,3 ation of Mass by 5. For a chemical equation to conform to the Law of conservation of Mass, A It has to be balanced B. the number of atoms must be change C. the mass of the reactant must be change D. products change into reactants in a chemical to form the chemical 6. What are the products in the equation below? MnO2 (s) + Al(s) – Al2O3 (s) + Mn (s) A. Al and Mn B. Al and MnO2 C. Al2O3 and Mn D. Al only pply the 7g to its 7. Which of the following chemical Equation is a combination Reaction? A. 2 Mg (s) + O2 â†’ 2MgO (s) B. 2KNO3 (S) 2KNO2( s) + O2 (s) C. Zn(s) + H2SO4 (aq) â†’ ZnSO4(s) + H2 (9) D. Mg3N2 Mg(s) + N2 (g) n 8. In the equation below, what are the reactants? H2O + SO3 â†’ H2SO4 A. Hands B. Hand O C. H2O and S D. H20 and SO3 9. Quicklime (Cao) is used as a drying agent. When water is added to this, slaked lime Ca(OH)2 is formed. What type of reaction is this? A. Combination B. Single displacement C. Decomposition D. Double displacementâ€‹

**Answer:**

di ko Po alam e sorry na lang at thank you

## 1. Given: Desired pH = 7.0 Actual pH reading =

**Ask: **1. Given: Desired pH = 7.0 Actual pH reading = 6.5 NVL for quicklime = 1.50 Pond area = 1.5 haâ€‹

**Answer:**

Final answer: 4.33 tons

**Explanation:**

carry on learning ðŸ™‚

## where is the quicklime camefrom

**Ask: **where is the quicklime camefrom

Answer:

Lime is produced through the calcination of limestone (calcium carbonate) in a lime kiln at temperatures at or above 2000 degrees Fahrenheit. The product of calcination of high calcium limestone is “quicklime” or calcium oxide. Quicklime in turn can be reacted with water to produce hydrated lime (calcium hydroxide).

Explanation:

## 11. During a chemical reactiona. atoms are destroyedc. elements are

**Ask: **

11. During a chemical reaction

a. atoms are destroyed

c. elements are destroyed

b atoms are rearranged

d. new elements are produced

12. A chemical reaction is a process in which

a. all reactants change state

c the law of conservation of mass applies

b. products change into reactants

d. all of these

13. What determines an atom’s ability to undergo chemical reactions?

a protons

b. neutrons

c. innermost electrons

d. outermost electrons

14. How is a chemical equation is balanced?

a. changing subscripts

c. adding coefficients

b. erasing elements as necessary

d adding elements as necessary

15. What are the products in the equation below? Zn + CuSO-> ZnSO4 + Cu

a. Zn and Cu b. Zn and Cus: c. ZnSO4 and Cu d Zn only

16. Which of the following is the correct balanced reaction?

a 2 C3Hs + 100 6CO2 + 8H20

c CsHe + O2 – 300, +2H20

b. C3Hs +0.

CO2 + H2O

d. CsHa + 50

300, 4H20

17. Quicklime (Cao) is used as a drying agent When water is added to this, slaked lime CalOH) is formed. What type of reaction is

this?

a combination bi single displacement c decomposition d. double displacement

18. Fresh fish and meat that are not stored in a refrigerator show signs of spoilage in less than a day What has caused this

spoilage?

a temperature changes b. presence of microorganisms c oxygen in air d. all of the above

19. The rate of reaction increases as the temperature increases Which of the following statements provides the best explanation for

this?

a. At lower temperatures the particles do not collide with each other

b. At higher temperatures the particles have more energy, move faster and collide more often

c. Higher temperature has higher activation energy

d Increasing the temperature increases the number of particles, so they collide more often

20. Which of the following statements about collisions is correct?

a Reaction will occur even without collision of molecules

b. All colliding particles have the same amount of energy

e Only fast-moving particles collide with each other.

d Reactions can happen if the colliding partides have enough energyâ€‹

**Answer:**

11.a

12.a

13.d

14.b

15.b

16.a

17.c

18.b

19.d

20.b

## 9. Percent Composition of calcium (Ca) in Quicklime, CaO is

**Ask: **9. Percent Composition of calcium (Ca) in Quicklime, CaO is A 28% B. 47 % C. 53% D. 71 %â€‹

**Answer:**

D.71%

**Explanation:**

The percent of calcium in CaO by mass is 71.47%

The percent of calcium in CaO by mass is 71.47%. This calculation involves determining the molar mass of calcium oxide

## what is the process to make quicklimeâ€‹

**Ask: **what is the process to make quicklimeâ€‹

**Answer:**

Put your calcium carbonate in the kiln.

Here you will begin the process of turning your rock mixture into quicklime. Heat your calcium carbonate directly on the flame until it becomes red hot. Do this for about 2-3 minutes. The rock will decompose on heating to create calcium oxide (quicklime) and carbon dioxide.

## calculate the percentage composition of following substances 1. quicklime, Ca0.

**Ask: **calculate the percentage composition of following substances

1. quicklime, Ca0.

2. Pyrite, FeS2.

3.CuBr2

4. (NH4)2S

5. N2S2â€‹

[tex]tt{huge{red{1. : Solution:}}}[/tex]

**Step 1:** Calculate the molar mass of CaO.

*Note that the molar masses of Ca and O are 40.08 g and 16.00 g, respectively.*

[tex]begin{aligned} text{molar mass of CaO} & = text{40.08 g + 16.00 g} \ & = text{56.08 g} end{aligned}[/tex]

**Step 2:** Solve for the percentage composition of CaO.

â€¢ **For Ca**

[tex]begin{aligned} %text{Ca} & = frac{n times text{molar mass of Ca}}{text{molar mass of CaO}} times 100% \ & = frac{1 times text{40.08 g}}{text{56.08 g}} times 100% \ & = boxed{71.47%} end{aligned}[/tex]

â€¢ **For ****O**

[tex]begin{aligned} %text{O} & = frac{n times text{molar mass of O}}{text{molar mass of CaO}} times 100% \ & = frac{1 times text{16.00 g}}{text{56.08 g}} times 100% \ & = boxed{28.53%} end{aligned}[/tex]

[tex]tt{huge{red{2. : Solution:}}}[/tex]

**Step 1:** Calculate the molar mass of FeSâ‚‚.

*Note that the molar masses of Fe and S are 55.85 g and 32.07 g, respectively.*

[tex]begin{aligned} text{molar mass of} : text{FeS}_2 & = text{55.85 g + 2(32.07 g)} \ & = text{119.99 g} end{aligned}[/tex]

**Step 2:** Solve for the percentage composition of FeSâ‚‚.

â€¢ **For Fe**

[tex]begin{aligned} %text{Fe} & = frac{n times text{molar mass of Fe}}{text{molar mass of} : text{FeS}_2} times 100% \ & = frac{1 times text{55.85 g}}{text{119.99 g}} times 100% \ & = boxed{46.55%} end{aligned}[/tex]

â€¢ **For S**

[tex]begin{aligned} %text{S} & = frac{n times text{molar mass of S}}{text{molar mass of} : text{FeS}_2} times 100% \ & = frac{2 times text{32.07 g}}{text{119.99 g}} times 100% \ & = boxed{53.45%} end{aligned}[/tex]

[tex]tt{huge{red{3. : Solution:}}}[/tex]

**Step 1:** Calculate the molar mass of CuBrâ‚‚.

*Note that the molar masses of Cu and Br are 63.55 g and 79.90 g, respectively.*

[tex]begin{aligned} text{molar mass of} : text{FeS}_2 & = text{63.55 g + 2(79.90 g)} \ & = text{223.35 g} end{aligned}[/tex]

**Step 2:** Solve for the percentage composition of CuBrâ‚‚.

â€¢ **For Cu**

[tex]begin{aligned} %text{Cu} & = frac{n times text{molar mass of Cu}}{text{molar mass of} : text{CuBr}_2} times 100% \ & = frac{1 times text{63.55 g}}{text{223.35 g}} times 100% \ & = boxed{28.45%} end{aligned}[/tex]

â€¢ **For Br**

[tex]begin{aligned} %text{Br} & = frac{n times text{molar mass of Br}}{text{molar mass of} : text{CuBr}_2} times 100% \ & = frac{2 times text{79.90 g}}{text{223.35 g}} times 100% \ & = boxed{71.55%} end{aligned}[/tex]

[tex]tt{huge{red{4. : Solution:}}}[/tex]

**Step 1:** Calculate the molar mass of (NHâ‚„)â‚‚S.

*Note that the molar masses of N, H, and S are 14.01 g, 1.008 g, and 32.07 g, respectively.*

[tex]begin{aligned} text{molar mass of} : (text{NH}_4)_2text{S} & = text{2(14.01 g) + 8(1.008 g) + 32.07 g} \ & = text{68.154 g} end{aligned}[/tex]

**Step 2:** Solve for the percentage composition of (NHâ‚„)â‚‚S.

â€¢ **For N**

[tex]begin{aligned} %text{N} & = frac{n times text{molar mass of N}}{text{molar mass of} : (text{NH}_4)_2text{S}} times 100% \ & = frac{2 times text{14.01 g}}{text{68.154 g}} times 100% \ & = boxed{41.11%} end{aligned}[/tex]

â€¢ **For H**

[tex]begin{aligned} %text{H} & = frac{n times text{molar mass of H}}{text{molar mass of} : (text{NH}_4)_2text{S}} times 100% \ & = frac{8 times text{1.008 g}}{text{68.154 g}} times 100% \ & = boxed{11.83%} end{aligned}[/tex]

â€¢ **For S**

[tex]begin{aligned} %text{S} & = frac{n times text{molar mass of S}}{text{molar mass of} : (text{NH}_4)_2text{S}} times 100% \ & = frac{1 times text{32.07 g}}{text{68.154 g}} times 100% \ & = boxed{47.06%} end{aligned}[/tex]

[tex]tt{huge{red{5. : Solution:}}}[/tex]

**Step 1:** Calculate the molar mass of Nâ‚‚Sâ‚‚.

*Note that the molar masses of N and S are 14.01 g and 32.07 g, respectively.*

[tex]begin{aligned} text{molar mass of} : text{N}_2text{S}_2 & = text{2(14.01 g) + 2(32.07 g)} \ & = text{92.16 g} end{aligned}[/tex]

**Step 2:** Solve for the percentage composition of Nâ‚‚Sâ‚‚.

â€¢ **For N**

[tex]begin{aligned} %text{N} & = frac{n times text{molar mass of N}}{text{molar mass of} : text{N}_2text{S}_2} times 100% \ & = frac{2 times text{14.01 g}}{text{92.16 g}} times 100% \ & = boxed{30.40%} end{aligned}[/tex]

â€¢ **For S**

[tex]begin{aligned} %text{N} & = frac{n times text{molar mass of S}}{text{molar mass of} : text{N}_2text{S}_2} times 100% \ & = frac{2 times text{32.07 g}}{text{92.16 g}} times 100% \ & = boxed{69.60%} end{aligned}[/tex]

———————————————————

** Note:** The value of n in the formula of percent composition is the subscript of each element in the compound. If there is no subscript, it means that the value of n is 1.

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__Note:__ Kindly swipe the screen to the left to see the continuation on the right side.

[tex]\[/tex]

#CarryOnLearning

## Quicklime(CaO) is used as a drying agent. When water is

**Ask: **Quicklime(CaO) is used as a drying agent. When water is added to this ,slaked lime Ca(OH) is formed.what type of reaction is this?

It is a combination reaction. More specifically, a hydration reaction because you added water.

Hey mate,

Here’s your answer

This is combination reaction as well as exothermic reaction.

This is combination reaction because more than one reactant is involved in this reaction to give a single product.

And

This is exothermic reaction because energy ( heat ) is released with Ca(OH) in this reaction.

Hope this helps!

Not only you can get the answer of **what happens when chemically when quicklime is added to water**, you could also find the answers of what is the, Quicklime(CaO) is used, erns as he, What happens chemically, and 1. Given: Desired.