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## If r varies directly as s and inversely as the

**Ask: **If r varies directly as s and inversely as the square of u, and r = 2 when s= 18 and u = 2 find:

a. r when u = 3 and s= 27. 3 .

b. s when u = 2 and r=4.

c. u when r = 1 and s= 36

ANSWER:

*b. s when u = 2 and r=4. FOR SURE*

**Answer:**

C

**Step-by-step explanation:**

sana makatulong kung ayaw ede wag

## if r varies directly as s and inversely as the

**Ask: **if r varies directly as s and inversely as the squre of u and r=2 when s=18 and u=2 a.find r when u=3 and s=27 b.find s when u=2 r=4 c.find u when r=1 s=36

r=[tex] frac{ks}{u^{2} } [/tex] 2=[tex] frac{k18}{2^{2} } [/tex] 2=[tex] frac{k18}{4 } [tex] frac{8}{18} [/tex]=[tex] frac{18}{18} [/tex] k=[tex] frac{8}{18} [/tex] k=**[tex] frac{4}{9} [/tex] a. **r=[tex] frac{ks}{u^{2} } r=[tex] frac{ frac{4}{9}27 }{3 ^{2} } [/tex] [tex] frac{ frac{4}{9}27 }{6 } [/tex] [tex] frac{12}{6} [/tex] r=2

## If r varies directly as s and inversely as the

**Ask: **If r varies directly as s and inversely as the square of u and r=2 when s=18and u=2

Find:

r when u=3 and s=27

s when u=2 and r=4

u when r=1 and s=36

**Answer:**

1.3

2.1

3.1/6

**Step-by-step explanation:**

## JOIN AND COMBINED VARIATIONS with solutionIf r varies directly as

**Ask: **JOIN AND COMBINED VARIATIONS with solution

If r varies directly as s and inversely as the square of u, and r = 2 when s=18 and u= 2, find the following

4. r, when u = 3 and s=27

5. s, when u = 2 and r=4

6. u, when r = 1 and s= 36

**Answer:**

SOLUTION

TO DETERMINE

The equation if r varies directly as s and inversely as the square of u, and r = 2 when s = 18 and u = 2

EVALUATION

Here it is given that r varies directly as s and inversely as the square of u

displaystyle sf{r propto : frac{s}{ {u}^{2} } }r∝

u

2

s

displaystyle sf{ implies : r = : frac{ks}{ {u}^{2} } }⟹r=

u

2

ks

Where k is variation constant

Now r = 2 , s = 18 , u = 2 gives

displaystyle sf{ implies : 2= : frac{k times 18}{ {2}^{2} } }⟹2=

2

2

k×18

displaystyle sf{ implies : k = frac{8}{18} }⟹k=

18

8

displaystyle sf{ implies : k = frac{4}{9} }⟹k=

9

4

Hence the required equation is

displaystyle sf{ : r = : frac{4s}{ 9{u}^{2} } }r=

9u

2

4s

━━━━━━━━━━━━━━━━

## 1. If r varies directly as s and inversely as

**Ask: **1. If r varies directly as s and inversely as the square of u, then r = 2 when s=18 and u=2 find:

a. r when u=3 and s=27

b.s when u=2 and r=4

c u when r=1 and s=36

**Answer:**

a po para sa akin correct po yn

## Solve the following: if r varies directly as s and

**Ask: **Solve the following:

if r varies directly as s and inversely as the square of u, and r=2 when s=18, and u=2, find:

a.) r when u=3 and s=27

b.) s when u=2 and r=4

c.) u when r=1 and s=36

EQUATION: r = ks/u²

2 = k (18)/(2)²

2 = k 18/4 ÷ 2/2

2 = k 9/2

2 ÷ 9/2 = k 9/2 ÷ 9/2

4/9 = k

a. r = (4/9)(27) / (3)²

r = 12 / 9

r = 4/3

ANSWER: r = 4/3

b. 4 = (4/9)s / (2)²

4 = 1/9s

4 ÷ 1/9 = 1/9s ÷ 1/9

36 = s

ANSWER: s = 36

c. 1 = (4/9)(36) / u²

1 = 16 / u²

√16 = √u²

±4 = u

ANSWER: u = ±4

## If r varies directly as sand inversely as the square

**Ask: ** If r varies directly as sand inversely as the square of u, and r = 2 when s = 18 and u = 2,

find:

a. r when u = 3 and s = 27.

b. s when u = 2 and r=4.

c. u when r = 1 and s = 36.

## Problem:

*If r varies directly as s and inversely as the square of u, and r = 2 when s = 18 and u = 2, find:*

a. r when u = 3 and s = 27.

b. s when u = 2 and r=4.

c. u when r = 1 and s = 36.

## Solution:

r = ks/u²

2 = k(18)/2²

2 = k(18)/4

2(4) = k(18)

8 = 18k

k = 8/18

k = 4/9

*a. r when u = 3 and s = 27*

r = ks/u²

r = (4/9)(27)/3²

r = (108/9)/9

r = 12/9

r = 4/3

*b. s when u = 2 and r = 4*

r = ks/u²

ru² = ks

s = ru²/k

s = 4(2²)/(4/9)

s = 4(4)/(4/9)

s = 16/(4/9)

s = 16(9/4)

s = 144/4

s = 36

*c. u when r = 1 and s = 36.*

r = ks/u²

ru² = ks

u² = ks/r

[tex][begin{array}{l}u = sqrt {frac{{ks}}{r}} \\u = sqrt {frac{{frac{4}{9}(36)}}{1}} \\u = sqrt {frac{{144}}{9}} \\u = sqrt {16} \\u = 4end{array}][/tex]

*#CarryOnLearning*

## if r varies directly as s and inversely as the

**Ask: **if r varies directly as s and inversely as the square of u and r=2 when s=18 and u=2 find;

s when u=2 and r=4

**Answer:**

s = 36

**Step-by-step explanation:**

[tex]r = frac{ks}{ {u}^{2} } [/tex]

[tex]2 = frac{18k}{ {2}^{2} } [/tex]

Multiply **2**** ****to**** ****2**

**[tex]2 = frac{18k}{4} [/tex]**

Multiply** ****2**** ****to**** ****4**

**[tex]8 = 18k[/tex]**

Divide **8**** ****to**** ****1****8**

[tex] frac{4}{9} = k[/tex]

[tex]4 = frac{ frac{4}{9}s }{4} [/tex]

Multiply** ****4**** ****to**** ****4**

[tex]16 = frac{4}{9} s[/tex]

Multiply both sides of the equation** ****9****/****4**

[tex] frac{64}{9} = s[/tex]

Divide **6****4**** ****to**** ****9**

**3****6**** ****=**** ****s**

I hope it’s help

Please brainliest me

## If r varies directly as s and inversely as the

**Ask: **If r varies directly as s and inversely as the square of u, and r=2 when s=18 and u=2, find

a. r when u=3 and s=27

b. s when u=2 and r=4

c/ u when r=1 and s=36

**Answer:**

A. R WHEN U=3 AND S=7 PA BRAINLEST PO

## -If r varies directly as s and inversely as the

**Ask: **–

If r varies directly as s and inversely as the square of u, and r = 2 whead

s=18 and u=2, find the following:

4. r, when u = 3 and s = 27

5. S, when u = 2 and r = 4

6.u, when r= 1 and s = 36

## Problem:

*If r varies directly as s and inversely as the square of u, and r = 2 when s = 18 and u = 2, find:*

a. r when u = 3 and s = 27.

b. s when u = 2 and r = 4.

c. u when r = 1 and s = 36.

## Solution:

r = ks/u²

2 = k(18)/2²

2 = k(18)/4

2(4) = k(18)

8 = 18k

k = 8/18

k = 4/9

*4. r when u = 3 and s = 27*

r = ks/u²

r = (4/9)(27)/3²

r = (108/9)/9

r = 12/9

r = 4/3

*5. s when u = 2 and r = 4*

r = ks/u²

ru² = ks

s = ru²/k

s = 4(2²)/(4/9)

s = 4(4)/(4/9)

s = 16/(4/9)

s = 16(9/4)

s = 144/4

s = 36

*6. u when r = 1 and s = 36.*

r = ks/u²

ru² = ks

u² = ks/r

[tex][begin{array}{l}u = sqrt {frac{{ks}}{r}} \\u = sqrt {frac{{frac{4}{9}(36)}}{1}} \\u = sqrt {frac{{144}}{9}} \\u = sqrt {16} \\u = 4end{array}][/tex]

*#CarryOnLearning*

Not only you can get the answer of **s when u=2 and r=4**, you could also find the answers of 1. If r, if r varies, -If r varies, If r varies, and JOIN AND COMBINED.