If you are looking for the answer of s when u=2 and r=4, you’ve got the right page. We have approximately 10 FAQ regarding s when u=2 and r=4. Read it below.
If r varies directly as s and inversely as the
Ask: If r varies directly as s and inversely as the square of u, and r = 2 when s= 18 and u = 2 find:
a. r when u = 3 and s= 27. 3 .
b. s when u = 2 and r=4.
c. u when r = 1 and s= 36
ANSWER:
b. s when u = 2 and r=4. FOR SURE
Answer:
C
Step-by-step explanation:
sana makatulong kung ayaw ede wag
if r varies directly as s and inversely as the
Ask: if r varies directly as s and inversely as the squre of u and r=2 when s=18 and u=2 a.find r when u=3 and s=27 b.find s when u=2 r=4 c.find u when r=1 s=36
r=[tex] frac{ks}{u^{2} } [/tex] 2=[tex] frac{k18}{2^{2} } [/tex] 2=[tex] frac{k18}{4 } [tex] frac{8}{18} [/tex]=[tex] frac{18}{18} [/tex] k=[tex] frac{8}{18} [/tex] k=[tex] frac{4}{9} [/tex] a. r=[tex] frac{ks}{u^{2} } r=[tex] frac{ frac{4}{9}27 }{3 ^{2} } [/tex] [tex] frac{ frac{4}{9}27 }{6 } [/tex] [tex] frac{12}{6} [/tex] r=2
If r varies directly as s and inversely as the
Ask: If r varies directly as s and inversely as the square of u and r=2 when s=18and u=2
Find:
r when u=3 and s=27
s when u=2 and r=4
u when r=1 and s=36
Answer:
1.3
2.1
3.1/6
Step-by-step explanation:
JOIN AND COMBINED VARIATIONS with solutionIf r varies directly as
Ask: JOIN AND COMBINED VARIATIONS with solution
If r varies directly as s and inversely as the square of u, and r = 2 when s=18 and u= 2, find the following
4. r, when u = 3 and s=27
5. s, when u = 2 and r=4
6. u, when r = 1 and s= 36
Answer:
SOLUTION
TO DETERMINE
The equation if r varies directly as s and inversely as the square of u, and r = 2 when s = 18 and u = 2
EVALUATION
Here it is given that r varies directly as s and inversely as the square of u
displaystyle sf{r propto : frac{s}{ {u}^{2} } }r∝
u
2
s
displaystyle sf{ implies : r = : frac{ks}{ {u}^{2} } }⟹r=
u
2
ks
Where k is variation constant
Now r = 2 , s = 18 , u = 2 gives
displaystyle sf{ implies : 2= : frac{k times 18}{ {2}^{2} } }⟹2=
2
2
k×18
displaystyle sf{ implies : k = frac{8}{18} }⟹k=
18
8
displaystyle sf{ implies : k = frac{4}{9} }⟹k=
9
4
Hence the required equation is
displaystyle sf{ : r = : frac{4s}{ 9{u}^{2} } }r=
9u
2
4s
━━━━━━━━━━━━━━━━
1. If r varies directly as s and inversely as
Ask: 1. If r varies directly as s and inversely as the square of u, then r = 2 when s=18 and u=2 find:
a. r when u=3 and s=27
b.s when u=2 and r=4
c u when r=1 and s=36
Answer:
a po para sa akin correct po yn
Solve the following: if r varies directly as s and
Ask: Solve the following:
if r varies directly as s and inversely as the square of u, and r=2 when s=18, and u=2, find:
a.) r when u=3 and s=27
b.) s when u=2 and r=4
c.) u when r=1 and s=36
EQUATION: r = ks/u²
2 = k (18)/(2)²
2 = k 18/4 ÷ 2/2
2 = k 9/2
2 ÷ 9/2 = k 9/2 ÷ 9/2
4/9 = k
a. r = (4/9)(27) / (3)²
r = 12 / 9
r = 4/3
ANSWER: r = 4/3
b. 4 = (4/9)s / (2)²
4 = 1/9s
4 ÷ 1/9 = 1/9s ÷ 1/9
36 = s
ANSWER: s = 36
c. 1 = (4/9)(36) / u²
1 = 16 / u²
√16 = √u²
±4 = u
ANSWER: u = ±4
If r varies directly as sand inversely as the square
Ask: If r varies directly as sand inversely as the square of u, and r = 2 when s = 18 and u = 2,
find:
a. r when u = 3 and s = 27.
b. s when u = 2 and r=4.
c. u when r = 1 and s = 36.
Problem:
If r varies directly as s and inversely as the square of u, and r = 2 when s = 18 and u = 2, find:
a. r when u = 3 and s = 27.
b. s when u = 2 and r=4.
c. u when r = 1 and s = 36.
Solution:
r = ks/u²
2 = k(18)/2²
2 = k(18)/4
2(4) = k(18)
8 = 18k
k = 8/18
k = 4/9
a. r when u = 3 and s = 27
r = ks/u²
r = (4/9)(27)/3²
r = (108/9)/9
r = 12/9
r = 4/3
b. s when u = 2 and r = 4
r = ks/u²
ru² = ks
s = ru²/k
s = 4(2²)/(4/9)
s = 4(4)/(4/9)
s = 16/(4/9)
s = 16(9/4)
s = 144/4
s = 36
c. u when r = 1 and s = 36.
r = ks/u²
ru² = ks
u² = ks/r
[tex][begin{array}{l}u = sqrt {frac{{ks}}{r}} \\u = sqrt {frac{{frac{4}{9}(36)}}{1}} \\u = sqrt {frac{{144}}{9}} \\u = sqrt {16} \\u = 4end{array}][/tex]
#CarryOnLearning
if r varies directly as s and inversely as the
Ask: if r varies directly as s and inversely as the square of u and r=2 when s=18 and u=2 find;
s when u=2 and r=4
Answer:
s = 36
Step-by-step explanation:
[tex]r = frac{ks}{ {u}^{2} } [/tex]
[tex]2 = frac{18k}{ {2}^{2} } [/tex]
Multiply 2 to 2
[tex]2 = frac{18k}{4} [/tex]
Multiply 2 to 4
[tex]8 = 18k[/tex]
Divide 8 to 18
[tex] frac{4}{9} = k[/tex]
[tex]4 = frac{ frac{4}{9}s }{4} [/tex]
Multiply 4 to 4
[tex]16 = frac{4}{9} s[/tex]
Multiply both sides of the equation 9/4
[tex] frac{64}{9} = s[/tex]
Divide 64 to 9
36 = s
I hope it’s help
Please brainliest me
If r varies directly as s and inversely as the
Ask: If r varies directly as s and inversely as the square of u, and r=2 when s=18 and u=2, find
a. r when u=3 and s=27
b. s when u=2 and r=4
c/ u when r=1 and s=36
Answer:
A. R WHEN U=3 AND S=7 PA BRAINLEST PO
-If r varies directly as s and inversely as the
Ask: –
If r varies directly as s and inversely as the square of u, and r = 2 whead
s=18 and u=2, find the following:
4. r, when u = 3 and s = 27
5. S, when u = 2 and r = 4
6.u, when r= 1 and s = 36
Problem:
If r varies directly as s and inversely as the square of u, and r = 2 when s = 18 and u = 2, find:
a. r when u = 3 and s = 27.
b. s when u = 2 and r = 4.
c. u when r = 1 and s = 36.
Solution:
r = ks/u²
2 = k(18)/2²
2 = k(18)/4
2(4) = k(18)
8 = 18k
k = 8/18
k = 4/9
4. r when u = 3 and s = 27
r = ks/u²
r = (4/9)(27)/3²
r = (108/9)/9
r = 12/9
r = 4/3
5. s when u = 2 and r = 4
r = ks/u²
ru² = ks
s = ru²/k
s = 4(2²)/(4/9)
s = 4(4)/(4/9)
s = 16/(4/9)
s = 16(9/4)
s = 144/4
s = 36
6. u when r = 1 and s = 36.
r = ks/u²
ru² = ks
u² = ks/r
[tex][begin{array}{l}u = sqrt {frac{{ks}}{r}} \\u = sqrt {frac{{frac{4}{9}(36)}}{1}} \\u = sqrt {frac{{144}}{9}} \\u = sqrt {16} \\u = 4end{array}][/tex]
#CarryOnLearning
Not only you can get the answer of s when u=2 and r=4, you could also find the answers of 1. If r, if r varies, -If r varies, If r varies, and JOIN AND COMBINED.
