# S When U=2 And R=4

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## If r varies directly as s and inversely as the

Ask: If r varies directly as s and inversely as the square of u, and r = 2 when s= 18 and u = 2 find:
a. r when u = 3 and s= 27. 3 .
b. s when u = 2 and r=4.
c. u when r = 1 and s= 36​

b. s when u = 2 and r=4. FOR SURE

C

Step-by-step explanation:

sana makatulong kung ayaw ede wag

## if r varies directly as s and inversely as the

Ask: if r varies directly as s and inversely as the squre of u and r=2 when s=18 and u=2 a.find r when u=3 and s=27 b.find s when u=2 r=4 c.find u when r=1 s=36

r=[tex] frac{ks}{u^{2} } [/tex] 2=[tex] frac{k18}{2^{2} } [/tex] 2=[tex] frac{k18}{4 } [tex] frac{8}{18} [/tex]=[tex] frac{18}{18} [/tex] k=[tex] frac{8}{18} [/tex] k=[tex] frac{4}{9} [/tex] a. r=[tex] frac{ks}{u^{2} } r=[tex] frac{ frac{4}{9}27 }{3 ^{2} } [/tex] [tex] frac{ frac{4}{9}27 }{6 } [/tex] [tex] frac{12}{6} [/tex] r=2

## If r varies directly as s and inversely as the

Ask: If r varies directly as s and inversely as the square of u and r=2 when s=18and u=2
Find:
r when u=3 and s=27
s when u=2 and r=4
u when r=1 and s=36

1.3

2.1

3.1/6

Step-by-step explanation:

## JOIN AND COMBINED VARIATIONS with solutionIf r varies directly as

Ask: JOIN AND COMBINED VARIATIONS with solution

If r varies directly as s and inversely as the square of u, and r = 2 when s=18 and u= 2, find the following

4. r, when u = 3 and s=27
5. s, when u = 2 and r=4
6. u, when r = 1 and s= 36​

SOLUTION

TO DETERMINE

The equation if r varies directly as s and inversely as the square of u, and r = 2 when s = 18 and u = 2

EVALUATION

Here it is given that r varies directly as s and inversely as the square of u

displaystyle sf{r propto : frac{s}{ {u}^{2} } }r∝

u

2

s

displaystyle sf{ implies : r = : frac{ks}{ {u}^{2} } }⟹r=

u

2

ks

Where k is variation constant

Now r = 2 , s = 18 , u = 2 gives

displaystyle sf{ implies : 2= : frac{k times 18}{ {2}^{2} } }⟹2=

2

2

k×18

displaystyle sf{ implies : k = frac{8}{18} }⟹k=

18

8

displaystyle sf{ implies : k = frac{4}{9} }⟹k=

9

4

Hence the required equation is

displaystyle sf{ : r = : frac{4s}{ 9{u}^{2} } }r=

9u

2

4s

━━━━━━━━━━━━━━━━

## 1. If r varies directly as s and inversely as

Ask: 1. If r varies directly as s and inversely as the square of u, then r = 2 when s=18 and u=2 find:
a. r when u=3 and s=27
b.s when u=2 and r=4
c u when r=1 and s=36

a po para sa akin correct po yn

## Solve the following: if r varies directly as s and

if r varies directly as s and inversely as the square of u, and r=2 when s=18, and u=2, find:

a.) r when u=3 and s=27
b.) s when u=2 and r=4
c.) u when r=1 and s=36

EQUATION: r = ks/u²

2 = k (18)/(2)²

2 = k 18/4 ÷ 2/2

2 = k 9/2

2 ÷ 9/2 = k 9/2 ÷ 9/2

4/9 = k

a. r = (4/9)(27) / (3)²

r = 12 / 9

r = 4/3

b. 4 = (4/9)s / (2)²

4 = 1/9s

4 ÷ 1/9 = 1/9s ÷ 1/9

36 = s

c. 1 = (4/9)(36) / u²

1 = 16 / u²

√16 = √u²

±4 = u

## If r varies directly as sand inversely as the square

Ask: If r varies directly as sand inversely as the square of u, and r = 2 when s = 18 and u = 2,
find:
a. r when u = 3 and s = 27.
b. s when u = 2 and r=4.
c. u when r = 1 and s = 36.​

## If r varies directly as s and inversely as the square of u, and r = 2 when s = 18 and u = 2, find:

a. r when u = 3 and s = 27.

b. s when u = 2 and r=4.

c. u when r = 1 and s = 36.​

r = ks/u²

2 = k(18)/2²

2 = k(18)/4

2(4) = k(18)

8 = 18k

k = 8/18

k = 4/9

r = ks/u²

r = (4/9)(27)/3²

r = (108/9)/9

r = 12/9

r = 4/3

r = ks/u²

ru² = ks

s = ru²/k

s = 4(2²)/(4/9)

s = 4(4)/(4/9)

s = 16/(4/9)

s = 16(9/4)

s = 144/4

s = 36

## c. u when r = 1 and s = 36.

r = ks/u²

ru² = ks

u² = ks/r

[tex][begin{array}{l}u = sqrt {frac{{ks}}{r}} \\u = sqrt {frac{{frac{4}{9}(36)}}{1}} \\u = sqrt {frac{{144}}{9}} \\u = sqrt {16} \\u = 4end{array}][/tex]

## if r varies directly as s and inversely as the

Ask: if r varies directly as s and inversely as the square of u and r=2 when s=18 and u=2 find;
s when u=2 and r=4​

s = 36

Step-by-step explanation:

[tex]r = frac{ks}{ {u}^{2} } [/tex]

[tex]2 = frac{18k}{ {2}^{2} } [/tex]

Multiply 2 to 2

[tex]2 = frac{18k}{4} [/tex]

Multiply 2 to 4

[tex]8 = 18k[/tex]

Divide 8 to 18

[tex] frac{4}{9} = k[/tex]

[tex]4 = frac{ frac{4}{9}s }{4} [/tex]

Multiply 4 to 4

[tex]16 = frac{4}{9} s[/tex]

Multiply both sides of the equation 9/4

[tex] frac{64}{9} = s[/tex]

Divide 64 to 9

36 = s

I hope it’s help

## If r varies directly as s and inversely as the

Ask: If r varies directly as s and inversely as the square of u, and r=2 when s=18 and u=2, find
a. r when u=3 and s=27
b. s when u=2 and r=4
c/ u when r=1 and s=36

A. R WHEN U=3 AND S=7 PA BRAINLEST PO

## -If r varies directly as s and inversely as the

If r varies directly as s and inversely as the square of u, and r = 2 whead
s=18 and u=2, find the following:
4. r, when u = 3 and s = 27
5. S, when u = 2 and r = 4
6.u, when r= 1 and s = 36​

## If r varies directly as s and inversely as the square of u, and r = 2 when s = 18 and u = 2, find:

a. r when u = 3 and s = 27.

b. s when u = 2 and r = 4.

c. u when r = 1 and s = 36.​

r = ks/u²

2 = k(18)/2²

2 = k(18)/4

2(4) = k(18)

8 = 18k

k = 8/18

k = 4/9

r = ks/u²

r = (4/9)(27)/3²

r = (108/9)/9

r = 12/9

r = 4/3

r = ks/u²

ru² = ks

s = ru²/k

s = 4(2²)/(4/9)

s = 4(4)/(4/9)

s = 16/(4/9)

s = 16(9/4)

s = 144/4

s = 36

## 6. u when r = 1 and s = 36.

r = ks/u²

ru² = ks

u² = ks/r

[tex][begin{array}{l}u = sqrt {frac{{ks}}{r}} \\u = sqrt {frac{{frac{4}{9}(36)}}{1}} \\u = sqrt {frac{{144}}{9}} \\u = sqrt {16} \\u = 4end{array}][/tex]

## #CarryOnLearning

Not only you can get the answer of s when u=2 and r=4, you could also find the answers of 1. If r, if r varies, -If r varies, If r varies, and JOIN AND COMBINED.