If you are looking for the answer of difference between when and whenever, you’ve got the right page. We have approximately 10 FAQ regarding difference between when and whenever. Read it below.

## heat transfer can occur between two object whenever

**Ask: **heat transfer can occur between two object whenever

Answer:

Explanation:

Whenever there is a temperature difference, heat transfer occurs. It may occur rapidly, as through a cooking pan, or slowly, as through the walls of a picnic ice chest. … (The matter is stationary on a macroscopic scale—we know that thermal motion of the atoms and molecules occurs at any temperature above absolute zero.)

**Answer:**

### Heat is transferred by three different methods: conduction, convection, and radiation.

hope it helps:))

## subtract then reduce the difference to lowest terms whenever possible

**Ask: **subtract then reduce the difference to lowest terms whenever possible

**Answer:**

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## It is a result whenever friction happened between environmental factors

**Ask: **It is a result whenever friction happened between environmental factors and the rock

**Answer:**

__E____a____r____t____h____q____u____a____k____e__** **is the answer.

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kindly correct me if i’m wrong, thank you.

## Reduce the difference to lowest terms whenever possible

**Ask: **Reduce the difference to lowest terms whenever possible

**Answer:**

1. 3/7

2. 1/4

3. 1/2

4. 1/2

5. 21 13/20

6. 10 1/3

7 .3/10

8. 2 1/4

9. 1/4

10. 2 7/10

**Answer:****. 3/7****2. 1/4****3. 1/2****4. 1/2****5. 21 13/20****6. 10 1/3****7 .3/10****8. 2 1/4****9. 1/4****10. 2 7/10**

**Step-by-step explanation:**

mark brainliest

## 17.Constructive interference of sound waves occurs _______________. A. when two

**Ask: **17.Constructive interference of sound waves occurs _______________.

A. when two waves arrive at the same point out of phase with each other

B. whenever there is an echo

C. when two waves arrive at the same point in phase with each other

D. whenever waves are refracted by air layers of different temperatures

C.and.D

**Explanation:**

pili k lng

**Answer:**

C.

**Explanation:**

*Constructive interference is a type of interference that occurs at any location along the medium where the two interfering waves have a displacement in the same direction.*

## Directions:Find the difference. Reduce the answer to lowest terms whenever

**Ask: **Directions:Find the difference. Reduce the answer to lowest terms whenever possible

**Step-by-step explanation:**

number 1 is

[tex] 21frac{7}{30}[/tex]

## A. find the difference. reduce the answer to lowest terms

**Ask: **A. find the difference. reduce the answer to lowest terms whenever possible

**Subtraction of Fractions and Mixed Numbers**

The result of subtracting fractions with fractions, mixed numbers with mixed numbers like the problem below is:

1. [tex]frac{6}{7}[/tex]-[tex]frac{3}{7}[/tex]=[tex]frac{3}{7}[/tex]

2. [tex]frac{5}{8}[/tex]-[tex]frac{3}{8}[/tex]=[tex]frac{2}{8}[/tex]=[tex]frac{1}{4}[/tex]

3. [tex]frac{9}{10}[/tex]-[tex]frac{4}{10}[/tex]=[tex]frac{5}{10}=frac{1}{2}[/tex]

4. [tex]frac{11}{12} -frac{5}{12} =frac{6}{12} =frac{1}{2}[/tex]

5. [tex]36frac{11}{15} -15frac{1}{12} =21frac{13}{20}[/tex]

6. [tex]100frac{14}{15} -90frac{9}{15}=10frac{1}{3}[/tex]

7. [tex]frac{9}{10} -frac{3}{5} =frac{3}{10}[/tex]

8. [tex]7frac{3}{4} -5frac{1}{2} =2frac{1}{4}[/tex]

9. [tex]frac{7}{12} -frac{1}{3} =frac{3}{12}[/tex]

10. [tex]63frac{3}{6} -60frac{4}{5} =2frac{7}{10}[/tex]

What are the steps to solve it so that the results like the above are obtained?

1. [tex]frac{6}{7}[/tex]-[tex]frac{3}{7}[/tex]=[tex]frac{6-3}{7}=frac{3}{7}[/tex] because the denominator is the same which is 7 then the numerator remains to be subtracted.

2. [tex]frac{5}{8}[/tex]-[tex]frac{3}{8}[/tex]=[tex]frac{5-3}{8}=frac{2}{8}[/tex]=[tex]frac{1}{4}[/tex] is the same as the solution above because the denominator is the same, namely 8.

3. [tex]frac{9}{10}[/tex]-[tex]frac{4}{10}[/tex]=[tex]frac{9-4}{10}=frac{5}{10}=frac{1}{2}[/tex] the solution is the same because the denominator is the same as the denominator then we simplify [tex]frac{5}{10}[/tex] by dividing each by 5, so [tex]frac{5}{10} =frac{5:5}{10:5} =frac{1}{2}[/tex]

4. [tex]frac{11}{12} -frac{5}{12} =frac{11-5}{12} =frac{6}{12} =frac{1}{2}[/tex] has the same way as number 1-3.

5. [tex]36frac{11}{15} -15frac{1}{12} =(36-15)+(frac{11}{15}-frac{1}{12})=[/tex]…

We immediately subtract the natural numbers, for the denominators 15 and 12 we find the least common multiple of the two numbers and we get 60 so that [tex](36-15)+(frac{11}{15}-frac{1}{12})=21+(frac{44}{60}-frac{5}{60} )=21frac{39}{60} =…[/tex]

We simplify [tex]frac{39}{60}[/tex] by dividing each by 3 so that [tex]21frac{39}{60} =21frac{39:3}{60:3} =21frac{13}{20}[/tex]

6. [tex]100frac{14}{15} -90frac{9}{15}=(100-90)+(frac{14}{15} -frac{9}{15} )=10+frac{5}{15}=…[/tex] for [tex]frac{5}{15}[/tex] we each divide by 5 to get the simplest form so [tex]10frac{5}{15}=10frac{5:5}{15:5} =10frac{1}{3}[/tex]

7. [tex]frac{9}{10} -frac{3}{5} =…[/tex]

We first make the denominator 10 because the least common multiple is 10, so that [tex]frac{9}{10} -frac{3}{5} =frac{9}{10}-frac{6}{10} =frac{9-6}{10} =frac{3}{10}[/tex]

8. [tex]7frac{3}{4} -5frac{1}{2} =(7-5)+(frac{3}{4} -frac{1}{2} )=2(frac{3}{4}-frac{2}{4}) =2frac{1}{4}[/tex] in the same way see the explanation above.

9. [tex]frac{7}{12} -frac{1}{3} =frac{7}{12}-frac{4}{12} = frac{3}{12}[/tex] in the same way see the explanation above.

10. [tex]63frac{3}{6} -60frac{4}{5} =(63-60)+(frac{3}{6}-frac{4}{5})=3frac{15-24}{30} =3frac{-9}{30} =…[/tex] We break 3=2+1 and for 1 we change it to [tex]frac{30}{30}[/tex]so that [tex]3frac{-9}{30} =2+1-frac{9}{30} =2+frac{30}{30} -frac{9}{30} =2frac{21}{30} =2frac{7}{10}[/tex]3

I hope this explanation can help you to understand subtraction of fractions with fractions or mixed numbers with fractions like the examples above.

And to strengthen your understanding, please open the following link: https://brainly.ph/question/2193148

#SPJ2

## Subtract. Reduce the difference to lowest terms whenever possible.

**Ask: **Subtract. Reduce the difference to lowest terms whenever possible.

**Answer:**

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**Step-by-step explanation:**

## find the differences. reduce the answer to lowest terms whenever

**Ask: **find the differences. reduce the answer to lowest terms whenever possible.

**Answer:**

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## Subtract. Reduce the difference to lowest terms whenever possible.

**Ask: **Subtract. Reduce the difference to lowest terms whenever possible.

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The *boxed** *fraction is the *lowest** **term** *of the exact answer…

Not only you can get the answer of **difference between when and whenever**, you could also find the answers of subtract then reduce, Directions:Find the difference., A. find the, 17.Constructive interference of, and Reduce the difference.